evaluate |x^(3)-1|when x = -1
asked by guest on Nov 18, 2024 at 6:33 am
You asked:
MathBot Answer:
∣x3−1∣=2\left\lvert {x}^{3} - 1\right\rvert = 2x3−1=2
∣x3−1∣=∣−(−1)3+1∣=∣1−−1∣=∣1+1∣=2\begin{aligned}\left|{x^{3} - 1}\right|&=\left|{- \left(-1\right)^{3} + 1}\right|\\&=\left|{1 - -1}\right|\\&=\left|{1 + 1}\right|\\&=2\end{aligned}x3−1=−(−1)3+1=∣1−−1∣=∣1+1∣=2