simplify: 14/(3x-21)+[(x+4)/((2x^2-6x-56)/(2x+3))]
asked by guest
on Apr 13, 2025 at 11:15 am
You asked:
Simplify the expression:
3x−2114+2x+32x2−6x−56x+4
MathBot Answer:
Simplified:
3x−2114+2x+32x2−6x−56x+4=x−7x+637
2x+32x2−6x−56x+4+3x−2114=2x2−6x−56(2x+3)(x+4)+3x−2114=3x−2114+2x−142x+3=2x−143x−2114⋅(2x−14)+3x−212x−14(2x+3)(3x−21)=x−7x+637
Expanded:
3x−2114+2x+32x2−6x−56x+4=2x+32x2−2x+36x−2x+356x+2x+32x2−2x+36x−2x+3564+3x−2114
Factored:
3x−2114+2x+32x2−6x−56x+4=6(x−7)6x+37