20000\left(1+x\right)^{20}+3800\left(\frac{\left(1+x\right)^{20}-1}{x}\right)+2000=0

asked by guest
on Mar 28, 2025 at 10:02 am



You asked:

Solve the equation 20000(1+x)20+3800⋅(1+x)20−1x+2000=020000 {\left( 1 + x \right)}^{20} + 3800 \cdot \frac{{\left( 1 + x \right)}^{20} - 1}{x} + 2000 = 0 for the variable xx.

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