4^3 + 2 √19 + 6

asked by guest
on Nov 17, 2024 at 1:33 pm



You asked:

Evaluate the expression: \({4}^{3} + 2 \cdot \sqrt{19} + 6\)

MathBot Answer:

\[{4}^{3} + 2 \cdot \sqrt{19} + 6 = 2 \sqrt{19} + 70 \approx 78.71779788708134710447396396771923\]


\[\begin{aligned}{4}^{3} + 2 \cdot \sqrt{19} + 6& = 4^{3} + 2 \cdot \sqrt{19} + 6\\& = 64 + 2 \cdot \sqrt{19} + 6\\& = \left(64 + 2 \cdot \sqrt{19}\right) + 6\\& = 70 + 2 \cdot \sqrt{19}\end{aligned}\]