1.02^x=2
You asked:
Solve the equation \({1.02}^{x} = 2\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{\log{\left(2 \right)}}{- \log{\left(51 \right)} + \log{\left(50 \right)}} \approx 35.002789\]
1.02^x=2
You asked:
MathBot Answer:
The solution is: \[x = - \frac{\log{\left(2 \right)}}{- \log{\left(51 \right)} + \log{\left(50 \right)}} \approx 35.002789\]