Math Problem Solver

\[ \frac{20}{4} + 6 - 3 + 5 + 2 = 15 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{20}{4}\), \(\frac{6}{1}\), \(\frac{-3}{1}\), \(\frac{5}{1}\), and \(\frac{2}{1}\) is \(4\). \[ \begin{aligned} \frac{20}{4} + 6 - 3 + 5 + 2 &= \frac{20 \cdot 1}{4 \cdot 1} + \frac{6 \cdot 4}{1 \cdot 4} + \frac{-3 \cdot 4}{1 \cdot 4} + \frac{5 \cdot 4}{1 \cdot 4} + \frac{2 \cdot 4}{1 \cdot 4} \\ &= \frac{20 + 24 + -12 + 20 + 8}{4} \\ &= \frac{60}{4} \\&= 15 \end{aligned} \]