(3p-2)(4p-1)
asked by guest on Mar 17, 2025 at 6:32 am
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MathBot Answer:
(3p−2)(4p−1)=(3p−2)(4p−1)\displaystyle \left(3 p - 2\right) \left(4 p - 1\right) = \left(3 p - 2\right) \left(4 p - 1\right) (3p−2)(4p−1)=(3p−2)(4p−1)
(3p−2)(4p−1)=12p2−11p+2\left(3 p - 2\right) \left(4 p - 1\right) = 12 p^{2} - 11 p + 2(3p−2)(4p−1)=12p2−11p+2