$\frac{x^4-2x^2+6x+3}{x-2}$

asked by guest
on Sep 20, 2024 at 8:27 am



You asked:

Evaluate the expression: \(\frac{{x}^{4} - 2 \cdot {x}^{2} + 6 x + 3}{x - 2}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{{x}^{4} - 2 \cdot {x}^{2} + 6 x + 3}{x - 2} = \frac{x^{4} - 2 x^{2} + 6 x + 3}{x - 2} \)


Expanded

\[\frac{{x}^{4} - 2 \cdot {x}^{2} + 6 x + 3}{x - 2} = \frac{x^{4}}{x - 2} - \frac{2 x^{2}}{x - 2} + \frac{6 x}{x - 2} + \frac{3}{x - 2}\]