y = 2x+3
50x + y^2 = 2
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MathBot Answer:
The system of equations has \(2\) solutions.
\[x = - \frac{31}{4} - \frac{\sqrt{933}}{4}, y = - \frac{\sqrt{933}}{2} - \frac{25}{2}\]\[x = - \frac{31}{4} + \frac{\sqrt{933}}{4}, y = - \frac{25}{2} + \frac{\sqrt{933}}{2}\]
Solve \(y = 2 x + 3\) for \(x\). \[x = \frac{y}{2} - \frac{3}{2}\]Substitute \(\frac{y}{2} - \frac{3}{2}\) for \(x\) in \(50 x + y^{2} = 2\) and simplify. $$\begin{aligned}50 x + y^{2} &= 2 \\ 50 \left(\frac{y}{2} - \frac{3}{2}\right) + y^{2} &= 2 \\ y^{2} + 25 y &= 77 \\y^{2} + 25 y - 77 &= 0 \\ y &= \frac{-(25) \pm \sqrt{(25)^{2} - 4(1)(-77)}}{2(25)} \\ y = - \frac{25}{2} + \frac{\sqrt{933}}{2}&, y = - \frac{\sqrt{933}}{2} - \frac{25}{2}\end{aligned}$$Substitute \(- \frac{25}{2} + \frac{\sqrt{933}}{2}\) into \(y = 2 x + 3\) to solve for \(x\). \[\begin{aligned}- \frac{25}{2} + \frac{\sqrt{933}}{2} &= 2 x + 3\\- 2 x &= \frac{31}{2} - \frac{\sqrt{933}}{2}\\x &= - \frac{31}{4} + \frac{\sqrt{933}}{4}\end{aligned}\]This yields the following solution. $$\begin{aligned}x = - \frac{31}{4} + \frac{\sqrt{933}}{4},\,y = - \frac{25}{2} + \frac{\sqrt{933}}{2}\end{aligned}$$Substitute \(- \frac{\sqrt{933}}{2} - \frac{25}{2}\) into \(y = 2 x + 3\) to solve for \(x\). \[\begin{aligned}- \frac{\sqrt{933}}{2} - \frac{25}{2} &= 2 x + 3\\- 2 x &= \frac{\sqrt{933}}{2} + \frac{31}{2}\\x &= - \frac{31}{4} - \frac{\sqrt{933}}{4}\end{aligned}\]This yields the following solution. $$\begin{aligned}x = - \frac{31}{4} - \frac{\sqrt{933}}{4},\,y = - \frac{\sqrt{933}}{2} - \frac{25}{2}\end{aligned}$$