y = -0.0002x^2 + 0.0412x + 0.1305

y=0.113

x=?

asked by guest
on Nov 18, 2024 at 11:14 am



You asked:

Given the following equations: \[\begin{aligned}y &= -\left( 0.0002 \cdot {x}^{2} \right) + 0.0412 x + 0.1305\\ y &= 0.113\end{aligned}\] Evaluate \(x\).

MathBot Answer:

The expression does not depend on the variable in the substitution.

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