-26+ $\sqrt{\2}$3+ $\sqrt{\2}$6

asked by guest
on Sep 21, 2024 at 9:53 am



You asked:

Evaluate the expression: \(-26 + \sqrt{2} \cdot 3 + \sqrt{2} \cdot 6\)

MathBot Answer:

\[-26 + \sqrt{2} \cdot 3 + \sqrt{2} \cdot 6 = -26 + 9 \sqrt{2} \approx -13.27207793864214456078480148211272\]

\[\begin{aligned}-26 + \sqrt{2} \cdot 3 + \sqrt{2} \cdot 6& = -26 + 3 \cdot \sqrt{2} + \sqrt{2} \cdot 6\\& = -26 + 3 \cdot \sqrt{2} + 6 \cdot \sqrt{2}\\& = \left(-26 + 3 \cdot \sqrt{2}\right) + 6 \cdot \sqrt{2}\\& = -26 + 9 \cdot \sqrt{2}\end{aligned}\]

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