(6-2)^3/(8/2*5-4)
asked by guest on Mar 31, 2025 at 1:34 pm
You asked:
MathBot Answer:
(6−2)382⋅5−4=4\frac{{\left( 6 - 2 \right)}^{3}}{\frac{8}{2} \cdot 5 - 4} = 428⋅5−4(6−2)3=4
(6−2)382⋅5−4=4382⋅5−4=6482⋅5−4=644⋅5−4=6420−4=6416=4\begin{aligned}\frac{{\left( 6 - 2 \right)}^{3}}{\frac{8}{2} \cdot 5 - 4}&=\frac{{4}^{3}}{\frac{8}{2} \cdot 5 - 4}\\&=\frac{64}{\frac{8}{2} \cdot 5 - 4}\\&=\frac{64}{4 \cdot 5 - 4}\\&=\frac{64}{20 - 4}\\&=\frac{64}{16}\\&=4\end{aligned}28⋅5−4(6−2)3=28⋅5−443=28⋅5−464=4⋅5−464=20−464=1664=4
