63x + 64y = 0
83x + 84z = 0
find z-y
You asked:
Given the following equations: \[\begin{aligned}63 x + 64 y &= 0\\ 83 x + 84 z &= 0\end{aligned}\] Evaluate \(z - y\).
MathBot Answer:
The system of linear equations has infinitely many solutions.
The substitutions are \( y = - \frac{63 x}{64} \), \( z = - \frac{83 x}{84} \).
\(x\) is a free variable.
\[z - y = - \frac{5 x}{1344}\]