What is the slope of the tangent at point (1,-1) of the curve given by the closed equation xy+3x^2+y^3=1?
Mathbot Says...
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What is the slope of the tangent at point (1,-1) of the curve given by the closed equation xy+3x^2+y^3=1?
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.