y[3ya+6]+3[3y+4]

asked by guest
on Mar 23, 2025 at 6:04 am



You asked:

Evaluate the expression: y(3ya+6)+3(3y+4)y \left(3 y a + 6\right) + 3 \left(3 y + 4\right)

MathBot Answer:

Evaluated



y(3ya+6)+3(3y+4)=y(3ay+6)+9y+12\displaystyle y \left(3 y a + 6\right) + 3 \left(3 y + 4\right) = y \left(3 a y + 6\right) + 9 y + 12

Expanded

y(3ya+6)+3(3y+4)=3y2a+15y+12y \left(3 y a + 6\right) + 3 \left(3 y + 4\right) = 3 y^{2} a + 15 y + 12

Factored

y(3ya+6)+3(3y+4)=3(y2a+5y+4)y \left(3 y a + 6\right) + 3 \left(3 y + 4\right) = 3 \left(y^{2} a + 5 y + 4\right)

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