2x²-{4(3x+2)-(5x²-3x+2)}
asked by guest on Mar 22, 2025 at 9:02 pm
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2x2−(4(3x+2)−(5x2−3x+2))=7x2−15x−6\displaystyle 2 {x}^{2} - \left(4 \left(3 x + 2\right) - \left(5 {x}^{2} - 3 x + 2\right)\right) = 7 x^{2} - 15 x - 6 2x2−(4(3x+2)−(5x2−3x+2))=7x2−15x−6
2x2−(4(3x+2)−(5x2−3x+2))=7x2−15x−62 {x}^{2} - \left(4 \left(3 x + 2\right) - \left(5 {x}^{2} - 3 x + 2\right)\right) = 7 x^{2} - 15 x - 62x2−(4(3x+2)−(5x2−3x+2))=7x2−15x−6