{ x }^{ 2 } +x ^ { 3 } -6x=0

asked by guest
on Jan 19, 2025 at 5:17 am



You asked:

Solve the equation \({x}^{2} + {x}^{3} - 6 x = 0\) for the variable \(x\).

MathBot Answer:

The 3 solutions to the equation are: \[\begin{aligned}x &= -3\\x &= 0\\x &= 2\end{aligned}\]