$(p-4)^{2}$+p(6p-q)

asked by guest
on Nov 15, 2024 at 12:33 am



You asked:

Evaluate the expression: \({\left( p - 4 \right)}^{2} + p \cdot \left(6 p - q\right)\)

MathBot Answer:

Evaluated



\(\displaystyle {\left( p - 4 \right)}^{2} + p \cdot \left(6 p - q\right) = p \left(6 p - q\right) + \left(p - 4\right)^{2} \)


Expanded

\[{\left( p - 4 \right)}^{2} + p \cdot \left(6 p - q\right) = 7 p^{2} - p q - 8 p + 16\]


Factored

\[{\left( p - 4 \right)}^{2} + p \cdot \left(6 p - q\right) = 7 p^{2} - p q - 8 p + 16\]