x ^ { 3 } +2x ^ { 2 } +x+5 \div x+2

asked by guest
on Mar 26, 2025 at 8:39 pm



You asked:

Evaluate the expression: x3+2x2+x+5x+2{x}^{3} + 2 {x}^{2} + x + \frac{5}{x} + 2

MathBot Answer:

Evaluated



x3+2x2+x+5x+2=x3+2x2+x+2+5x\displaystyle {x}^{3} + 2 {x}^{2} + x + \frac{5}{x} + 2 = x^{3} + 2 x^{2} + x + 2 + \frac{5}{x}

Factored

x3+2x2+x+5x+2=x4+2x3+x2+2x+5x{x}^{3} + 2 {x}^{2} + x + \frac{5}{x} + 2 = \frac{x^{4} + 2 x^{3} + x^{2} + 2 x + 5}{x}

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