3(p+q-6)
asked by guest on Apr 01, 2025 at 9:43 am
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MathBot Answer:
3(p+q−6)=3p+3q−18\displaystyle 3 \left(p + q - 6\right) = 3 p + 3 q - 18 3(p+q−6)=3p+3q−18
3(p+q−6)=3p+3q−183 \left(p + q - 6\right) = 3 p + 3 q - 183(p+q−6)=3p+3q−18