Integrate[Integrate[Divide[x,Power[\(40)xy+1\(41),2]],{y,0,1}],{x,0,1}]
You asked:
Evaluate the integral: \(\int_{0}^{1}{\int_{0}^{1}{\frac{x}{{\left( x y + 1 \right)}^{2}}}dy}dx\)
MathBot Answer:
Definite integral
\[\int_{0}^{1}{\int_{0}^{1}{\frac{x}{{\left( x y + 1 \right)}^{2}}}dy}dx = 1 - \log{\left(2 \right)} \approx 0.30685281944005469058276787854182\]