solve y''+3y'+2y=4

asked by guest
on Nov 26, 2024 at 5:22 pm



You asked:

Solve the equation y′′+3⋅y′+2y=4y^{\prime \prime} + 3 \cdot y^{\prime} + 2 y = 4 for the variable yy.

MathBot Answer:

y(t)=2+C1e−2t+C2e−ty{\left(t \right)} = 2 + C_{1} e^{- 2 t} + C_{2} e^{- t}

C1C_{1}, C2C_{2} are arbitrary constants.

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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