$e^{-4x}$ = y′

asked by guest
on Jan 20, 2025 at 5:26 pm



You asked:

Investigate the equation: \({e}^{-\left( 4 x \right)} = y^{\prime}\).

MathBot Answer:

\[y{\left(x \right)} = - \frac{e^{- 4 x}}{4} + C_{1}\]

\(C_{1}\) is an arbitrary constant.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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