𝑦(6𝑦^2−𝑥−1)𝑑𝑥 + 2𝑥𝑑𝑦 = 0

asked by guest
on Nov 22, 2024 at 12:01 pm



You asked:

Investigate the equation: \(y\left( 6 {y}^{2} - x - 1 \right) \cdot d x + 2 x d y = 0\).

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