slope 1/5 and y-intercept -3
You asked:
Find an equation of the line with slope \(\frac{1}{5}\) and y-intercept \((0, -3)\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{1}{5} \\ A =& -1, B = 5 \end{aligned}$$$$\begin{aligned}-1 x + 5 y + C &= 0 \\ -1(0) + 5(-3) + C &= 0 \\ 0 + -15 + C &= 0 \\ 0 + C &= 15 \\ C &= 15 \end{aligned}$$An equation of the line in standard form is: $- x + 5 y + 15 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= \frac{1}{5}x + b \\ -3 &= \frac{1}{5} \times 0 + b \\ -3 &= 0 + b \\ b &= -3 \end{aligned}$$The slope-intercept form of the line is: $y = \frac{x}{5} - 3$.