x+1 x3+2x2+x+4\sqrt{x^3+2x^2+x+4}x3+2x2+x+4
asked by guest on Jan 29, 2025 at 1:54 am
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x+1x3+2x2+x+4=x+x3+2x2+x+4\displaystyle x + 1 \sqrt{{x}^{3} + 2 {x}^{2} + x + 4} = x + \sqrt{x^{3} + 2 x^{2} + x + 4} x+1x3+2x2+x+4=x+x3+2x2+x+4
x+1x3+2x2+x+4=x+x3+2x2+x+4x + 1 \sqrt{{x}^{3} + 2 {x}^{2} + x + 4} = x + \sqrt{x^{3} + 2 x^{2} + x + 4}x+1x3+2x2+x+4=x+x3+2x2+x+4