Find 𝑑𝑦/𝑑𝑥 when,𝑥=cos𝜃+cos2𝜃, 𝑦= sin𝜃+sin2𝜃

asked by guest
on Feb 01, 2025 at 5:52 am



You asked:

Calculate the value of ddx[y(x)]\frac{d}{dx}\left[y\left( x \right)\right] when x=cos⁡(θ)+cos⁡(2θ)x = \cos\left( θ \right) + \cos\left( 2 θ \right) and y=sin⁡(θ)+sin⁡(2θ)y = \sin\left( θ \right) + \sin\left( 2 θ \right).

MathBot Answer:

ddxy(x)=ddxy(x)\frac{d}{d x} y{\left(x \right)} = \frac{d}{d x} y{\left(x \right)}

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