$\frac{\SIN(A+B)+SIN(A-B)}{\COS(A+B)+COS(A-B)}$

asked by guest
on Nov 15, 2024 at 7:51 am



You asked:

Evaluate the expression: sin⁡(A+B)+sin⁡(A−B)cos⁡(A+B)+cos⁡(A−B)\frac{\sin\left( A + B \right) + \sin\left( A - B \right)}{\cos\left( A + B \right) + \cos\left( A - B \right)}

MathBot Answer:

Evaluated



sin⁡(A+B)+sin⁡(A−B)cos⁡(A+B)+cos⁡(A−B)=sin⁡(A−B)+sin⁡(A+B)cos⁡(A−B)+cos⁡(A+B)\displaystyle \frac{\sin\left( A + B \right) + \sin\left( A - B \right)}{\cos\left( A + B \right) + \cos\left( A - B \right)} = \frac{\sin{\left(A - B \right)} + \sin{\left(A + B \right)}}{\cos{\left(A - B \right)} + \cos{\left(A + B \right)}}

Expanded

sin⁡(A+B)+sin⁡(A−B)cos⁡(A+B)+cos⁡(A−B)=sin⁡(A−B)cos⁡(A−B)+cos⁡(A+B)+sin⁡(A+B)cos⁡(A−B)+cos⁡(A+B)\frac{\sin\left( A + B \right) + \sin\left( A - B \right)}{\cos\left( A + B \right) + \cos\left( A - B \right)} = \frac{\sin{\left(A - B \right)}}{\cos{\left(A - B \right)} + \cos{\left(A + B \right)}} + \frac{\sin{\left(A + B \right)}}{\cos{\left(A - B \right)} + \cos{\left(A + B \right)}}

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