13+N-(b)-1.962=0
na=nb*m
13*0.6-(a)*0.9-n*0.9=0
You asked:
Solve the system of equations:\[\begin{aligned}13 + N - b - 1.962 &= 0\\n a &= n b m\\13 \cdot 0.6 - a \cdot 0.9 - n \cdot 0.9 &= 0\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}N &= b - \frac{5519}{500}\\a &= \frac{26}{3}\\n &= 0\end{aligned}$$\(b\) is a free variable.
\(m\) is a free variable.