x^3+2x^2-5x-6=
asked by guest on Mar 30, 2025 at 6:01 am
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x3+2x2−5x−6=x3+2x2−5x−6\displaystyle {x}^{3} + 2 {x}^{2} - 5 x - 6 = x^{3} + 2 x^{2} - 5 x - 6 x3+2x2−5x−6=x3+2x2−5x−6
x3+2x2−5x−6=(x−2)(x+1)(x+3){x}^{3} + 2 {x}^{2} - 5 x - 6 = \left(x - 2\right) \left(x + 1\right) \left(x + 3\right)x3+2x2−5x−6=(x−2)(x+1)(x+3)