(3/(x+2))-(2/(x-1))
asked by guest on Feb 01, 2025 at 4:44 am
You asked:
MathBot Answer:
3x+2−2x−1=3x+2−2x−1\displaystyle \frac{3}{x + 2} - \frac{2}{x - 1} = \frac{3}{x + 2} - \frac{2}{x - 1} x+23−x−12=x+23−x−12
3x+2−2x−1=3x+2−2x−1\frac{3}{x + 2} - \frac{2}{x - 1} = \frac{3}{x + 2} - \frac{2}{x - 1}x+23−x−12=x+23−x−12
3x+2−2x−1=x−7(x−1)(x+2)\frac{3}{x + 2} - \frac{2}{x - 1} = \frac{x - 7}{\left(x - 1\right) \left(x + 2\right)}x+23−x−12=(x−1)(x+2)x−7