\frac{\sqrt{6-x}-2}{\sqrt{3-x}-1}

asked by guest
on Apr 04, 2025 at 10:21 am



You asked:

Evaluate the expression: 6−x−23−x−1\frac{\sqrt{6 - x} - 2}{\sqrt{3 - x} - 1}

MathBot Answer:

Evaluated



6−x−23−x−1=6−x−23−x−1\displaystyle \frac{\sqrt{6 - x} - 2}{\sqrt{3 - x} - 1} = \frac{\sqrt{6 - x} - 2}{\sqrt{3 - x} - 1}

Expanded

6−x−23−x−1=6−x3−x−1−23−x−1\frac{\sqrt{6 - x} - 2}{\sqrt{3 - x} - 1} = \frac{\sqrt{6 - x}}{\sqrt{3 - x} - 1} - \frac{2}{\sqrt{3 - x} - 1}

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