\left(x^2+y^2-4y+4\right)^{\frac{1}{2}}\left(x^2+y^2+4y+4\right)^{\frac{1}{2}}=6

asked by guest
on Jan 10, 2025 at 7:41 pm



You asked:

Investigate the equation: \({\left( {x}^{2} + {y}^{2} - 4 y + 4 \right)}^{\frac{1}{2}} {\left( {x}^{2} + {y}^{2} + 4 y + 4 \right)}^{\frac{1}{2}} = 6\).

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