y'-2xy=x

asked by guest
on Nov 24, 2024 at 5:43 am



You asked:

Investigate the equation: \(y^{\prime} - 2 x y = x\).

MathBot Answer:

\[y{\left(x \right)} = - \frac{1}{2} + C_{1} e^{x^{2}}\]

\(C_{1}\) is an arbitrary constant.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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