|2^(x+1) - 1|<|2^x -8|
You asked:
Solve the inequality \( \left\lvert {2}^{x + 1} - 1\right\rvert < \left\lvert {2}^{x} - 8\right\rvert \) for the variable \(x\).
MathBot Answer:
\[x < \frac{\log{\left(3 \right)}}{\log{\left(2 \right)}}\]
|2^(x+1) - 1|<|2^x -8|
You asked:
MathBot Answer:
\[x < \frac{\log{\left(3 \right)}}{\log{\left(2 \right)}}\]