(3*(-3^(2 ) )+2^(0 ))/7^(5 ) =

asked by guest
on Nov 17, 2024 at 3:37 pm



You asked:

Evaluate the expression: 3⋅−32+2075\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}}

MathBot Answer:

3⋅−32+2075=−2616807≈−0.00154697447492116380079728684477\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}} = - \frac{26}{16807} \approx -0.00154697447492116380079728684477

3⋅−32+2075=3⋅−9+2075=−27+2075=−27+175=−2675=−2616807\begin{aligned}\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}}&=\frac{3 \cdot -9 + {2}^{0}}{{7}^{5}}\\&=\frac{-27 + {2}^{0}}{{7}^{5}}\\&=\frac{-27 + 1}{{7}^{5}}\\&=\frac{-26}{{7}^{5}}\\&=\frac{-26}{16807}\end{aligned}

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