(3*(-3^(2 ) )+2^(0 ))/7^(5 ) =
You asked:
Evaluate the expression: \(\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}}\)
MathBot Answer:
\[\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}} = - \frac{26}{16807} \approx -0.00154697447492116380079728684477\]
\[\begin{aligned}\frac{3 \cdot -{3}^{2} + {2}^{0}}{{7}^{5}}& = \left(3 \cdot -1 \cdot 3^{2} + 2^{0}\right) \cdot \frac{1}{7^{5}}\\& = \left(3 \cdot -1 \cdot 9 + 2^{0}\right) \cdot \frac{1}{7^{5}}\\& = \left(-3 \cdot 9 + 2^{0}\right) \cdot \frac{1}{7^{5}}\\& = \left(-27 + 2^{0}\right) \cdot \frac{1}{7^{5}}\\& = \left(-27 + 1\right) \cdot \frac{1}{7^{5}}\\& = -26 \cdot \frac{1}{7^{5}}\\& = \frac{-26}{16807}\\& = - \frac{26}{16807}\end{aligned}\]