$e^{2x}$ ( $2x^{2}$ - 8x -4) = 0
You asked:
Investigate the equation: \({e}^{2 x} \cdot \left(2 {x}^{2} - 8 x - 4\right) = 0\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}x &= 2 + \sqrt{6} \approx 4.4494897\\x &= 2 - \sqrt{6} \approx -0.44948974\end{aligned}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).