Divide[\(40)Power[a,2]+Power[R,2]+2aRCos[θ]\(41)\(40)Power[x,2]+Power[R,2]-2xRCos[θ]\(41),\(40)Power[a,2]+Power[R,2]-2aRCos[θ]\(41)\(40)Power[x,2]+Power[R,2]-2aRCos[θ]\(41)]=1
asked by guest
on Mar 30, 2025 at 12:12 am
You asked:
Investigate the equation:
(a2+R2−2aRcos(θ))(x2+R2−2aRcos(θ))(a2+R2+2aRcos(θ))(x2+R2−2xRcos(θ))=1.