Divide[\(40)Power[a,2]+Power[R,2]+2aRCos[θ]\(41)\(40)Power[x,2]+Power[R,2]-2xRCos[θ]\(41),\(40)Power[a,2]+Power[R,2]-2aRCos[θ]\(41)\(40)Power[x,2]+Power[R,2]-2aRCos[θ]\(41)]=1

asked by guest
on Mar 30, 2025 at 12:12 am



You asked:

Investigate the equation: (a2+R2+2aRcos(θ))(x2+R22xRcos(θ))(a2+R22aRcos(θ))(x2+R22aRcos(θ))=1\frac{\left({a}^{2} + {R}^{2} + 2 a R \cos\left( θ \right)\right) \left({x}^{2} + {R}^{2} - 2 x R \cos\left( θ \right)\right)}{\left({a}^{2} + {R}^{2} - 2 a R \cos\left( θ \right)\right) \left({x}^{2} + {R}^{2} - 2 a R \cos\left( θ \right)\right)} = 1.