solve d^3y/dx^3+d^2y/ dx^2-dy/dx-y=e^2x + cos 2x

asked by guest
on Jan 09, 2025 at 9:42 pm



You asked:

Investigate the equation: \(\frac{{d}^{3} y}{d {x}^{3}} + \frac{{d}^{2} y}{d {x}^{2}} - \frac{d y}{d x} - y = {e}^{2} x + \cos\left( 2 x \right)\).

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