Y=x^3/2+0.9sin(kx) /3-x

asked by guest
on Nov 28, 2024 at 9:41 am



You asked:

Investigate the equation: \(Y = \frac{{x}^{3}}{2} + \frac{0.9 \cdot \sin\left( k x \right)}{3} - x\).

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