16−$cos^{2}$4β−$sin^{2}$4β =

asked by guest
on Sep 19, 2024 at 8:58 pm



You asked:

Evaluate the expression: \(16 - {\cos\left( 4 β \right)}^{2} - {\sin\left( 4 β \right)}^{2}\)

MathBot Answer:

\[16 - {\cos\left( 4 β \right)}^{2} - {\sin\left( 4 β \right)}^{2} = - \sin^{2}{\left(4 β \right)} - \cos^{2}{\left(4 β \right)} + 16\]