[8๐(๐ฅ)โ(xหฃโบยน(๐ฅโ1)!)-(๐ฅโ8๐ฅยฒโ4๐ฅln๐ฅโlnยฒ๐ฅโ(4๐ฅ+2ln๐ฅ)ln2๐)]
asked by guest
on Nov 15, 2024 at 6:05 pm
You asked:
Evaluate the expression:
8โ
e(x)โ
xx+1โ
(xโ1)!โโ(xโ8x2โ4xln(x)โln(x)2โ(4x+2ln(x))โ
ln(2ฯ))
MathBot Answer:
Evaluated
8โ
e(x)โ
xx+1โ
(xโ1)!โโ(xโ8x2โ4xln(x)โln(x)2โ(4x+2ln(x))โ
ln(2ฯ))=8x2+4xlog(x)โx+8xx+1(xโ1)!โe(x)+(4x+2log(x))log(2ฯ)+log(x)2
Expanded
8โ
e(x)โ
xx+1โ
(xโ1)!โโ(xโ8x2โ4xln(x)โln(x)2โ(4x+2ln(x))โ
ln(2ฯ))=8x2+4xlog(x)โx+4xlog(2)+4xlog(ฯ)+8xxx(xโ1)!โe(x)+log(x)2+2log(2)log(x)+2log(x)log(ฯ)
Factored
8โ
e(x)โ
xx+1โ
(xโ1)!โโ(xโ8x2โ4xln(x)โln(x)2โ(4x+2ln(x))โ
ln(2ฯ))=8x2+4xlog(x)โx+4xlog(2)+4xlog(ฯ)+8xxx(xโ1)!โe(x)+log(x)2+2log(2)log(x)+2log(x)log(ฯ)