2(y-1)+3(2y-2)=4-2y

asked by guest
on Apr 07, 2025 at 4:20 am



You asked:

Solve the equation 2(y−1)+3(2y−2)=4−2y2 \left(y - 1\right) + 3 \left(2 y - 2\right) = 4 - 2 y for the variable yy.

MathBot Answer:

The solution is: y=65=1.2y = \frac{6}{5} = 1.2

8y−8=4−2y10y=12y=65\begin{aligned}8 y - 8 &= 4 - 2 y\\10 y &= 12\\y &= \frac{6}{5}\end{aligned}

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