Simplify {(2/3)^2}^3*(1/3)^-4*(3)^-1*(6)^-1
You asked:
Simplify the expression: \({{\left( \frac{2}{3} \right)}^{2}}^{3} \cdot {\left( \frac{1}{3} \right)}^{-4} \cdot {3}^{-1} \cdot {6}^{-1}\)
MathBot Answer:
Simplified:
\[ {{\left( \frac{2}{3} \right)}^{2}}^{3} \cdot {\left( \frac{1}{3} \right)}^{-4} \cdot {3}^{-1} \cdot {6}^{-1} = \frac{32}{81} = 0.\overline{395061728} \]