d^2+16d+64
asked by guest on Mar 20, 2025 at 5:59 pm
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MathBot Answer:
d2+16d+64=d2+16d+64\displaystyle {d}^{2} + 16 d + 64 = d^{2} + 16 d + 64 d2+16d+64=d2+16d+64
d2+16d+64=(d+8)2{d}^{2} + 16 d + 64 = \left(d + 8\right)^{2}d2+16d+64=(d+8)2