Math Problem Solver

$$15 + 9=24$$

$$\begin{aligned} \overset{\mathtt{1}}{\mathtt{1}}\mathtt{5}\\ \mathtt{+\phantom{0}}\phantom{0}\mathtt{9}\\ \hline \mathtt{2}\mathtt{4} \end{aligned}$$

$4$ is the digit in the $10^{0}$ place. $5 \times 10^{0} + 9 \times 10^{0} = 14 \times 10^{0} = 1 \times 10^{1} + 4 \times 10^{0}$.$1 \times 10^{1}$ carries to the $10^{1}$ place.

$2$ is the digit in the $10^{1}$ place. $1 \times 10^{1} + 1 \times 10^{1} + 0 \times 10^{1} = 2 \times 10^{1}$.