( a\sqrt{a}a+4 b\sqrt{b}b)( a\sqrt{a}a-2 b\sqrt{b}b )
asked by guest on Mar 20, 2025 at 11:54 am
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(a+4b)(a−2b)=(a−2b)(a+4b)\displaystyle \left(\sqrt{a} + 4 \sqrt{b}\right) \left(\sqrt{a} - 2 \sqrt{b}\right) = \left(\sqrt{a} - 2 \sqrt{b}\right) \left(\sqrt{a} + 4 \sqrt{b}\right) (a+4b)(a−2b)=(a−2b)(a+4b)
(a+4b)(a−2b)=2ab+a−8b\left(\sqrt{a} + 4 \sqrt{b}\right) \left(\sqrt{a} - 2 \sqrt{b}\right) = 2 \sqrt{a} \sqrt{b} + a - 8 b(a+4b)(a−2b)=2ab+a−8b