( a\sqrt{a}+4 b\sqrt{b})( a\sqrt{a}-2 b\sqrt{b} )

asked by guest
on Mar 20, 2025 at 11:54 am



You asked:

Evaluate the expression: (a+4b)(a2b)\left(\sqrt{a} + 4 \sqrt{b}\right) \left(\sqrt{a} - 2 \sqrt{b}\right)

MathBot Answer:

Evaluated



(a+4b)(a2b)=(a2b)(a+4b)\displaystyle \left(\sqrt{a} + 4 \sqrt{b}\right) \left(\sqrt{a} - 2 \sqrt{b}\right) = \left(\sqrt{a} - 2 \sqrt{b}\right) \left(\sqrt{a} + 4 \sqrt{b}\right)


Expanded

(a+4b)(a2b)=2ab+a8b\left(\sqrt{a} + 4 \sqrt{b}\right) \left(\sqrt{a} - 2 \sqrt{b}\right) = 2 \sqrt{a} \sqrt{b} + a - 8 b