log x-2log x+3 log(x+1)-log(x^2-1)

asked by guest
on Feb 01, 2025 at 4:17 am



You asked:

Evaluate the expression: log⁡(x)−2log⁡(x)+3log⁡(x+1)−log⁡(x2−1)\log\left( x \right) - 2 \log\left( x \right) + 3 \log\left( x + 1 \right) - \log\left( {x}^{2} - 1 \right)

MathBot Answer:

log⁡(x)−2log⁡(x)+3log⁡(x+1)−log⁡(x2−1)=−log⁡(x)−log⁡(x2−1)+3log⁡(x+1)\log\left( x \right) - 2 \log\left( x \right) + 3 \log\left( x + 1 \right) - \log\left( {x}^{2} - 1 \right) = - \log{\left(x \right)} - \log{\left(x^{2} - 1 \right)} + 3 \log{\left(x + 1 \right)}

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