dy/dx y=ln (x^2+2x/x^2-3x)

asked by guest
on Sep 21, 2024 at 4:36 am



You asked:

Investigate the equation: \(\frac{d y}{d x y} = \ln\left( {x}^{2} + \frac{2 x}{{x}^{2}} - 3 x \right)\).

+ Submit Question