$\sqrt{3y^2}$ $\sqrt{6y}$

asked by guest
on Nov 17, 2024 at 9:39 am



You asked:

Evaluate the expression: \(\sqrt{3 \cdot {y}^{2}} \cdot \sqrt{6 y}\)

MathBot Answer:

\[\sqrt{3 \cdot {y}^{2}} \cdot \sqrt{6 y} = 3 \sqrt{2} \sqrt{y} \sqrt{y^{2}}\]

If the variable\(y\) is real, then: \[3 \sqrt{2} \sqrt{y} \sqrt{y^{2}} = 3 \sqrt{2} \sqrt{y} \left|{y}\right|\]